Markdown in Python: List items with 5 spaces

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(This report comes from a [list discussion](http://sourceforge.net/mailarchive/forum.php?thread_name=ab8662790906170521s77037cccw3fc574ca11b41008%40mail.gmail.com&forum_name=python-markdown-discuss) as reported by Mikael Garde Nielsen.)

When parsing a list item (as the first item in a list) which starts with five spaces after the asterisk, Markdown crashes with an IndexError in the blockparser.

>>> markdown.markdown('*     list')
    ---------------------------------------------------------------------------
    IndexError                                Traceback (most recent call last)
    ...
    --> 295                 self.parser.parseBlocks(lst[-1], [item])
    IndexError: child index out of range

Additionally, when an item with five spaces it not the first item in a list, the output is weird/incorrect:

>>> markdown.markdown('* one\n*     five')
    <ul>
    <li>one<p>five</p>
    </li>
    </ul>

As opposed to:

>>> markdown.markdown('* one\n*    four')
    <ul>
    <li>one</li>
    <li>four</li>
    </ul>

Loose lists are also interesting:

>>> markdown.markdown('* one\n\n*     five\n')
    <ul>
    <li>
    <p>one</p>
    </li>
    <li>
    <pre><code>five
    </code></pre>
    </li>
    </ul>

It could be argued that that is correct, but Babelmark disagrees (see <http://babelmark.bobtfish.net/?markdown=*+one%0D%0A%0D%0A*+++++five>).

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